3x^2=60^2

Solution for 3x^2=60^2 equation:

3x^2=60^2

We move all terms to the left:

3x^2-(60^2)=0

We add all the numbers together, and all the variables

3x^2-3600=0

a = 3; b = 0; c = -3600;
Δ = b2-4ac
Δ = 02-4·3·(-3600)
Δ = 43200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{43200}=\sqrt{14400*3}=\sqrt{14400}*\sqrt{3}=120\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-120\sqrt{3}}{2*3}=\frac{0-120\sqrt{3}}{6}
=-\frac{120\sqrt{3}}{6}
=-20\sqrt{3}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+120\sqrt{3}}{2*3}=\frac{0+120\sqrt{3}}{6}
=\frac{120\sqrt{3}}{6}
=20\sqrt{3}
$